⇦ | ⇨ |
Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
Options
(a) 100g
(b) 1008g
(c) 108g
(d) 1050g
Correct Answer:
1008g
Explanation:
6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.
Related Questions: - How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
- The covalent bond length is the shortest in which one of the following bonds
- When ethyl iodide and propyl iodide react with Na in the presence of ether,they
- Which of the following species contains equal number of σ- and π-bonds
- Melting point is the higher for
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
- The covalent bond length is the shortest in which one of the following bonds
- When ethyl iodide and propyl iodide react with Na in the presence of ether,they
- Which of the following species contains equal number of σ- and π-bonds
- Melting point is the higher for
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply