| ⇦ | 
| ⇨ |
In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Thomas slag is
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- Volume concentration of 1.5 N H₂O₂ is
- What is the weight of oxygen required for the complete combusion of 2.8 kg of ethylene?
- If the value of Cp for nitrogen gas is 7 JK⁻¹mol⁻¹ , then the value
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Thomas slag is
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- Volume concentration of 1.5 N H₂O₂ is
- What is the weight of oxygen required for the complete combusion of 2.8 kg of ethylene?
- If the value of Cp for nitrogen gas is 7 JK⁻¹mol⁻¹ , then the value
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇