In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE

In Hydrogen Atom Energy Of First Excited State Is 34 Chemistry Question

In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom

Options

(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV

Correct Answer:

+3.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. If α is dissociation constant, then the total number of moles for the reaction
  2. Which of the following will not displace hydrogen
  3. In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
  4. When primary alcohol is oxidised with chlorine, it gives
  5. Acetic acid will be obtained on oxidation of

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE

Leave a Reply

Your email address will not be published.


*