| ⇦ | 
| ⇨ |
0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH. The basicity of acid is
Options
(a) 2
(b) 4
(c) 1
(d) 3
Correct Answer:
2
Explanation:
Gram equivalent of acid = gram equivalent of KOH (0.45 / E)= 20 x 0.5 / 1000
So, E=45
Equivalent weight= Molecular weight / Basicity
So, Basicity=90/45=2
Related Questions: - What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³
- The solubility of anhydrous AlCl₃ and hydrous AlCl₃ in diethylether are S₁
- Gasoline has composition
- The best coagulant for the precipitation of Fe(OH)₃ is
- Which one of the following elements has the maximum electron affinity?
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³
- The solubility of anhydrous AlCl₃ and hydrous AlCl₃ in diethylether are S₁
- Gasoline has composition
- The best coagulant for the precipitation of Fe(OH)₃ is
- Which one of the following elements has the maximum electron affinity?
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply