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0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH. The basicity of acid is
Options
(a) 2
(b) 4
(c) 1
(d) 3
Correct Answer:
2
Explanation:
Gram equivalent of acid = gram equivalent of KOH (0.45 / E)= 20 x 0.5 / 1000
So, E=45
Equivalent weight= Molecular weight / Basicity
So, Basicity=90/45=2
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Question Type: Memory
(964)
Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ammonia gas dissolves in water to form NH₄OH.In this reaction water acts as
- The equilibrium constant for mutarotation α-D Glucose ⇌ β-D Glucose is 1.8.
- Action of acetylene on dilute H₂SO₄ gives
- How many moles of iodine are liberated when 1 mole of potassium dichromate
- In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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