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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three objects coloured black, gray and white can withstand hostile conditions upto 2800⁰C.
- The surface temperature of the sun which has maximum energy
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
- As per Bohr model, the minimum energy (in eV) required to remove an electron
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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