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Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - The electronic configuration of chalcogens is
- Which of the following pairs of substance on reaction will not evolve H₂ gas
- If the gas at constant temperature and pressure expands, then its
- Which one of the following has maximum laevorotatory nature
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electronic configuration of chalcogens is
- Which of the following pairs of substance on reaction will not evolve H₂ gas
- If the gas at constant temperature and pressure expands, then its
- Which one of the following has maximum laevorotatory nature
- Neutral divalent carbon species released as reaction intermediate in reaction
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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