| ⇦ | 
| ⇨ |
Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - ΔG = ΔH – TΔS was given by
- Formation of methyl tertiary butyl ether by the reaction of sodium tertiary
- The general molecular formula for a cycloalkyl group is
- Chlorine is in +1 oxidation state in which of the following
- If 0.189g of chlorine containing organic compound gave 0.287g of silver chloride
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- ΔG = ΔH – TΔS was given by
- Formation of methyl tertiary butyl ether by the reaction of sodium tertiary
- The general molecular formula for a cycloalkyl group is
- Chlorine is in +1 oxidation state in which of the following
- If 0.189g of chlorine containing organic compound gave 0.287g of silver chloride
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply