⇦ | ![]() | ⇨ |
The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap bubble of surface area 40 cm², in joules is
Options
(a) 1.2×10⁻⁴
(b) 2.4×10⁻⁴
(c) 12×10⁻⁴
(d) 24×10⁻⁴
Correct Answer:
2.4×10⁻⁴
Explanation:
Given: Surface tension of a soap solution,
T = 0.03 N/m
Surface area, A = 40 cm² = 40 x 10⁻⁴ m²
Since the soap has two surfaces,
.·. Work done, W = T x 24
= 0.03 x 2 40 x 10⁻⁴ = 2.4 x 10⁻⁴J
Related Questions:
- Which of the following is a vector quantity?
- The minimum wavelength of X-rays produced in a Collidge tube operated
- The component of vector A=2i+3j along the vector i+j is
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- What is the time taken by moon light to reach earth?
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply