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If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - When temperature of an ideal gas is increased from 27⁰C to 227⁰C,
- When photons of energy hν fall on an aluminium plate (of work function E₀),
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When temperature of an ideal gas is increased from 27⁰C to 227⁰C,
- When photons of energy hν fall on an aluminium plate (of work function E₀),
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
- A black body is at 727⁰C. It emits energy at a rate which is proportional to
- The two ends of a rod of length L and a uniform cross-sectional area
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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