| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply