| ⇦ |
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- Light of wavelength λᴀ and λᴃ falls on two identical metal plates A and B respectively.
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- An adiabatic process occurs at constant
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- Light of wavelength λᴀ and λᴃ falls on two identical metal plates A and B respectively.
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- An adiabatic process occurs at constant
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply