| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - A ball is dropped from the root of a tower of height h
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- Laser beams are used to measure long distance because
- The transverse nature of electromagnetic waves is proved by which of the following?
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ball is dropped from the root of a tower of height h
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- Laser beams are used to measure long distance because
- The transverse nature of electromagnetic waves is proved by which of the following?
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply