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The particle executing simple harmonic motion has a kinetic energy K₀ cos²ωt. The maximum values of the potential energy and the total energy are respectively
Options
(a) K₀/2 and K₀
(b) K₀ and 2 K₀
(c) K₀ and K₀
(d) 0 and 2 K₀
Correct Answer:
K₀ and K₀
Explanation:
Kinetic energy + Potential energy = total energy
When kinetic energy is maximum, potential energy is zero and vice versa.
.·. Maximum potential energy = total energy
0 + K₀ = K₀
(K.E + P.E = Total energy) .
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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