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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bicyclist comes to a skidding stop in 10 m.During this process, the force
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- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- The wing span of an aeroplane is 20 m. It is flying in a field where the vertical
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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