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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Curie temperature above which
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- Two coherent sources of different intensities send waves which interfere.
- Three identical spheres, each of mass 3 kg are placed touching each other
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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