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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two lenses of power 15 D and -3 D are placed in contact.
- The Davisson- Germer experiment is the direct evidence of
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- Which one of the following statements is not correct in case of a semiconductor?
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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