| ⇦ | 
| ⇨ |
The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
Related Questions: - A body projected vertically from the earth reaches a height equal to earth’s radius
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
- The ratio of minimum wavelengths of Lyman and Balmer series will be
- Energy in a current carrying coil is stored in the form of
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body projected vertically from the earth reaches a height equal to earth’s radius
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
- The ratio of minimum wavelengths of Lyman and Balmer series will be
- Energy in a current carrying coil is stored in the form of
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply