| ⇦ | 
| ⇨ |
M⁺³ ion loses 3e⁻. Its oxidation number will be
Options
(a) 0
(b) 3
(c) 6
(d) -3
Correct Answer:
6
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In Cr₂O₇²⁻ the oxidation numbers are
- Standard enthalpy of vaporisation Δvap H⁰ for water at 100⁰C is 40.66 kJ mol⁻¹.
- By which one of the following compounds both CH₄ and CH₃ – CH₃ can be prepared
- In Lassaigne’s test red colour precipitate is obtained which is due to formation
- If ionization potential for hydrogen atom is 13.6eV, then ionization potential
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Cr₂O₇²⁻ the oxidation numbers are
- Standard enthalpy of vaporisation Δvap H⁰ for water at 100⁰C is 40.66 kJ mol⁻¹.
- By which one of the following compounds both CH₄ and CH₃ – CH₃ can be prepared
- In Lassaigne’s test red colour precipitate is obtained which is due to formation
- If ionization potential for hydrogen atom is 13.6eV, then ionization potential
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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