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At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:
Options
(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x
Correct Answer:
(283 / 383) x
Explanation:
Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- The induced emf in a coil of 10 H inductance in which current varies
- Light of wavelength λ from a point source falls on a small circular obstacle
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Very good one..
I saw same answer on other site as well but they were too lengthy.