| ⇦ | 
| ⇨ |
The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at
Options
(a) t = 1 s
(b) t = 0.5 s
(c) t = 0.25 s
(d) t = 2 s
Correct Answer:
t = 1 s
Explanation:
When angular acceleration is zero then torque on the wheel becomes zero.
θ(t) = 2t – 6t
dθ / dt = 6t – 12t
= dθ / dt = 12t – 12 = 0
t = 1 s
Related Questions: - A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- Maximum kinetic energy of electrons emitted in photoelectric effect increases when
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- Depletion layer contains
- Which of the following pairs of quantities does not have same dimensional
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- Maximum kinetic energy of electrons emitted in photoelectric effect increases when
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- Depletion layer contains
- Which of the following pairs of quantities does not have same dimensional
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply