| ⇦ | 
| ⇨ |
Two thin long conductors seprated by a distance d carry currents I₁ and I₂ in the same direction. They exert a force F on each other. Now, the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of force between them is
Options
(a) (-2F)
(b) F/3
(c) (-2F/3)
(d) (-F/3)
Correct Answer:
(-2F/3)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A boat taken 2h to travel 8km and back in still water.If the velocity of water 4 km/h
- Zenor diode is used for
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boat taken 2h to travel 8km and back in still water.If the velocity of water 4 km/h
- Zenor diode is used for
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical
- The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply