| ⇦ | 
| ⇨ |
The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye lens varies from
Options
(a) 9 D to 8 D
(b) 40 D to 32 D
(c) 44 D to 40 D
(d) None of these
Correct Answer:
44 D to 40 D
Explanation:
An eye see distant objects with full relaxation.
So, [1 / (2.5 × 10⁻²)] – [1 / -∞] = 1 / f or, P = 1 / f = 1 / 2.5 × 10⁻² = 40 D
An eye see an object at 25 cm with strain [1 / (2.5 × 10⁻²)] – [1 / 2.5 × 10⁻²] = 1 / f
.·. P = 1 / f = 40 + 4 = 44 D
Related Questions: - A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- In Young’s double slit experiment, the intensity of light coming from the first slit
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- A solenoid of length l metre has self inductance L henry. If number of turns
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- In Young’s double slit experiment, the intensity of light coming from the first slit
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- A solenoid of length l metre has self inductance L henry. If number of turns
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply