| ⇦ | 
| ⇨ |
A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
Related Questions: - The order of distance of an electron revolving in an atom from nucleus is
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of distance of an electron revolving in an atom from nucleus is
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply