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The periodic waves of intensities I₁ and I₂ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is:
Options
(a) I₁ + I₂
(b) (√I₁ + √I₂)²
(c) (√I₁ – √I₂)²
(d) 2 (I₁ + I₂)
Correct Answer:
2 (I₁ + I₂)
Explanation:
The resultant intensity of two periodic waves at a point is given by
I = I₁ + I₂ + 2 √I₁I₂ . cos ?.
Resultant intensity is max. if cos ? = -1
i.e Iₘₐₓ = I₁ + I₂ + 2 √I₁I₂
Resultant intensity is min. if cos ? = +1
i.e, Iₘᵢₙ = I₁ + I₂ – 2 √I₁I₂
Therefore, the sum of the max. and min. intensities is Iₘₐₓ + Iₘᵢₙ
= I₁ + I₂ + 2 √I₁I₂ + I₁ + I₂ – 2 √I₁I₂
= 2 (I₁ + I₂)
Related Questions: - Two waves of same amplitude superpose. The resultant intensity is I₁
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A transistor is operated in common emitter configuration at constant collector
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- A lens having focal length f and aperture of diameter d forms an image of intensity I
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two waves of same amplitude superpose. The resultant intensity is I₁
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A transistor is operated in common emitter configuration at constant collector
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- A lens having focal length f and aperture of diameter d forms an image of intensity I
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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