| ⇦ | 
| ⇨ |
A ray of light passes from a medium A having refractive index 1.6 to the medium B having refractive index 1.5. The value of critical angle of medium A is……..
Options
(a) sin⁻¹ √16/15
(b) sin⁻¹(16/15)
(c) sin⁻¹(1/2)
(d) sin⁻¹(15/16)
Correct Answer:
sin⁻¹(15/16)
Explanation:
As the law of refraction, we have
sin i(c) / sin 90° = 1.5 / 1.6
Therefore sin i(c) = 15 / 16
where i(c) = critical angle of medium, A = sin⁻¹ (15 / 16)
Related Questions: - The horizontal range and maximum height attained by a projectile are R and H,respectively
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- A charge of 100 μC has a potential at a distance of 9 m is
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- A charge of 100 μC has a potential at a distance of 9 m is
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply