⇦ | ⇨ |
The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å. The refractive index of material will be
Options
(a) 1.5
(b) 3
(c) 1.33
(d) 1.4
Correct Answer:
3
Explanation:
By using v = nλ , n = 2 x 10¹⁴ Hz
λ = 5000Å = 5000 x 10⁻¹⁰ m
v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s
Refractive index of the material,
µ = c / v = 3 x 10⁸ / 10⁸ = 3
Related Questions: - A particle executes simple harmonic oscillations with an amplitude
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A particle moves in a circle of radius 5 cm with constant speed and time period
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle executes simple harmonic oscillations with an amplitude
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A particle moves in a circle of radius 5 cm with constant speed and time period
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply