| ⇦ | 
| ⇨ |
Vanadium (III) oxide is a strong
Options
(a) drying agent
(b) oxidising agent
(c) reducing agent
(d) wetting agent
Correct Answer:
reducing agent
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If the equivalent weight of an element is 32, then the percentage of oxygen
- If a gas expands at constant temperature , it indicates that
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- Terfenadine is commonly used as a
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the equivalent weight of an element is 32, then the percentage of oxygen
- If a gas expands at constant temperature , it indicates that
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- Terfenadine is commonly used as a
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply