| ⇦ |
| ⇨ |
Vanadium (III) oxide is a strong
Options
(a) drying agent
(b) oxidising agent
(c) reducing agent
(d) wetting agent
Correct Answer:
reducing agent
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the following change,KMnO₄ → MnO₂, the oxidation state of Mn changes as
- The compound that gives both iodoform and Fehling’s tests is
- preservative among the following is
- Which of the following oxides is not expected to react with sodium hydroxide
- Tincture iodine is
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the following change,KMnO₄ → MnO₂, the oxidation state of Mn changes as
- The compound that gives both iodoform and Fehling’s tests is
- preservative among the following is
- Which of the following oxides is not expected to react with sodium hydroxide
- Tincture iodine is
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply