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Which of the following will show a negative deviation from Raoult’s law
Options
(a) Acetone-benzene
(b) Acetone-ethanol
(c) Benzene-methanol
(d) Acetone-chloroform
Correct Answer:
Acetone-chloroform
Explanation:
Hydrogen bonds are formed on mixing acetone and chloroform. The new interactions in the mixture are stronger than in the pure components. ΔV and ΔH are negative. The solution shows negative deviation.
Related Questions: - Among the following the most reactive towards alcoholic KOH is
- In methane four C-H bonds are directed towards the corners of
- Which is insoluble in water
- If heat of formation of C + O₂ → 2CO is ΔH = -110.5 kcal,then heat of combustion
- Which electronic configuration of an element has abnormally high difference
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Among the following the most reactive towards alcoholic KOH is
- In methane four C-H bonds are directed towards the corners of
- Which is insoluble in water
- If heat of formation of C + O₂ → 2CO is ΔH = -110.5 kcal,then heat of combustion
- Which electronic configuration of an element has abnormally high difference
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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