| ⇦ | 
| ⇨ |
How many grams of dibasic acid (mol.wt.200) should be present in 100 mL. of an aqueous solution to give decinormal strength
Options
(a) 1 g
(b) 10 g
(c) 2 g
(d) 20 g
Correct Answer:
1 g
Explanation:
Normality = Number of g. equivalents of solute / volume of solution (L).
Number of equivalents = Weight / Equivalent weight.
For dibasic acid, equivalent weight = molecular wt/2 = 200/2 = 100.
Volume of solution = 100 mL = 0.1 L. Normality = 0.1 N.
Weight of solute = equivalent weight ⨯ normality ⨯ volume of solution (L) = 100⨯ 0.1 ⨯ 0.1 = 1 g.
Related Questions: - In which of the following pairs of molecules/ions, the central atoms have
- Terylene is used for making
- The number of moles of acidified KMnO₄ required to oxidise one mole
- Chloropicrin is obtained by the reaction of
- The volume of water to be added to 100 cm³ of 0.5 N H₂SO₄ to get decinormal
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following pairs of molecules/ions, the central atoms have
- Terylene is used for making
- The number of moles of acidified KMnO₄ required to oxidise one mole
- Chloropicrin is obtained by the reaction of
- The volume of water to be added to 100 cm³ of 0.5 N H₂SO₄ to get decinormal
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply