| ⇦ | 
| ⇨ |
When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles are respectively
Options
(a) 8 α,7 β
(b) 4 α,7 β
(c) 4 α,4 β
(d) 4 α,1 β
Correct Answer:
4 α,1 β
Explanation:
α-particle = ₂He⁴, β-particle = ₋₁β and Nucleus = zXᴬ
Change in A occurs only due to α-emission.
Change in A = 228 – 212 = 16
This change is due to 4 α.
Again change in Z = 90 – 83 = 7
Change in Z due to 4α = 8
.·. Change in Z due to β = 8 – 7 = 1
This is due to one β.
Hence particles emitted = 4α, 1β.
Related Questions: - The potential difference applied to an X-ray tube is 5 kV and the current through it
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
- The product of pressure and volume hve thesame units as the product of
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential difference applied to an X-ray tube is 5 kV and the current through it
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
- The product of pressure and volume hve thesame units as the product of
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply