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In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- An LCR circuit contains resistance of 100 ohm and a supply of 200 volt at 300 radian
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- A current is flowing through resistance. A potential difference of 120 V
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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