In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second

⇦

⇨

In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)

Options

(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J

Correct Answer:

576×10¹² J

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

1. The ratio of radii of planets A and B is K₁ and ratio of accelerations
2. A parallel plate condenser with a dielectric of dielectric constant K between the plates
3. An ideal black body is equivalent to
4. An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
5. A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series

Topics: Radioactivity (83)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends