| ⇦ | 
| ⇨ |
The weight of a body on surface of earth is 12.6 N. When it is raised to a height half the radius of earth its weight will be
Options
(a) 2.8 N
(b) 5.6 N
(c) 12.6 N
(d) 25.2 N
Correct Answer:
5.6 N
Explanation:
Weight of body on the surface of earth, mg=12.6 N
At height h, the value of g’ is given by
g’=g (R/R+(R/2))²
=g 4/9
Weight at height, h=mg 4/9
h=12.6×4/9 =5.6 N
Related Questions: - An engine has an efficiency of 1/6. When the temperature of sink is reduced
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
- The wave function (in SI unit) for a light wave is given as Ψ(x,t)= 10³ sin π
- The distance travelled by a particle starting from rest and moving with an acceleration
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An engine has an efficiency of 1/6. When the temperature of sink is reduced
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
- The wave function (in SI unit) for a light wave is given as Ψ(x,t)= 10³ sin π
- The distance travelled by a particle starting from rest and moving with an acceleration
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply