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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The minimum wavelength of X-rays emitted by X-ray tube is 0.4125Å
- The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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