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A particle of masses m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is
Options
(a) √( 2GM / R)
(b) √( 2GM / R)²
(c) √( 2G R²)
(d) √( 2GM / R)²
Correct Answer:
√( 2GM / R)
Explanation:
The velocity u should be equal to the escape velocity. That is, u = √(2gR)
But g = GM / R² ⇒ u = √(2 . GM / R² . R)
√( 2GM / R)
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- If |A x B|= √3 A.B , then the value of |A + B| is
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In a semiconductor
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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