| ⇦ |
| ⇨ |
The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is
Options
(a) 3.60 M
(b) 0.36 M
(c) 0.72 M
(d) 1.08 M
Correct Answer:
0.72 M
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An alkane with a molecular formula C₆H₁₄ reacts with chlorine in the presence
- How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
- The solubility of I₂ increases in water in the presence of
- Which of the following is the least stable and its existence is doubtful
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alkane with a molecular formula C₆H₁₄ reacts with chlorine in the presence
- How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
- The solubility of I₂ increases in water in the presence of
- Which of the following is the least stable and its existence is doubtful
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Reaction is of zero order as the unit of rate constant is mol L⁻¹ S⁻¹
.·. Concentration of B =k × t =0.6×10⁻³ × 20 × 60 = 0.72 M
Let at time t=0 (A)= a and (B)=0
At time t=(20*60)sec (A)= (a-x) and (B)=x then
For 1st order reaction
(A’) =(A) – kt
: a-x = a – 0.6*10-3*20*60
Solving it will give
X= 0.72 M