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Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Options
(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Correct Answer:
O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Explanation:
According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻
Related Questions: - If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C
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Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- When primary alcohol is oxidised with chlorine, it gives
- Formula of gypsum is
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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