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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The moment of inertia of a semicircular ring about the centre is
- A block of mass m moving at a velocity v collides with another block of mass 2m
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The moment of inertia of a semicircular ring about the centre is
- A block of mass m moving at a velocity v collides with another block of mass 2m
- An electron moving in a uniform magnetic field of induction of intensity B,
- A parallel plate air capacitor is charged to a potential difference of V volts.
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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