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The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). The angle of minimum deviation is
Options
(a) 180⁰-3 A
(b) 180⁰-2 A
(c) 90⁰- A
(d) 180⁰+2 A
Correct Answer:
180⁰-2 A
Explanation:
Refractive index, μ = sin (A+Dm / 2) / sin (A/2)
cot (A / 2) = sin (A+Dm / 2) / sin (A/2)
cos (A/2) / sin (A/2) = sin (A+Dm / 2) / sin (A/2)
sin [(π/2) – (A/2)] = sin [(A + Dm) / 2]
(π / 2) – (A / 2) = (A / 2) + (Dm / 2)
Dm = π – 2A
Angle of minimum deviation, Dm = 180° – 2A
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric field in a certain region is given by E=5i ̂-3ĵ kV/m. The potential
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- The drift speed of electrons in copper wire of diameter and length l is v.
- White light reflected from a soap film (Refractive Index =1.5) has a maxima
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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