⇦ | ⇨ |
In Young’s double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is
Options
(a) sin⁻¹ 0.01
(b) sin⁻¹ 0.0001
(c) sin⁻¹ 0.001
(d) sin⁻¹ 0.1
Correct Answer:
sin⁻¹ 0.001
Explanation:
sin θ = λ / d
= 589 × 10⁻⁹ / 0.589 × 10⁻³ = 10⁻³ = 1 / 1000 = 0.001
Therefore, θ = sin⁻¹ 0.001
Related Questions: - Two lenses of power 15 D and -3 D are placed in contact.
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A boy standing at the top of a tower of 20m height drops a stone
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two lenses of power 15 D and -3 D are placed in contact.
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A boy standing at the top of a tower of 20m height drops a stone
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply