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In Young’s double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is
Options
(a) sin⁻¹ 0.01
(b) sin⁻¹ 0.0001
(c) sin⁻¹ 0.001
(d) sin⁻¹ 0.1
Correct Answer:
sin⁻¹ 0.001
Explanation:
sin θ = λ / d
= 589 × 10⁻⁹ / 0.589 × 10⁻³ = 10⁻³ = 1 / 1000 = 0.001
Therefore, θ = sin⁻¹ 0.001
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
- The angular velocity of second’s hand of a watch is
- The potential energy of a weightless spring compressed by a distance D is proportional
- what is the de-Broglie wavelength of the electron accelerated through a potential
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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