| ⇦ |
| ⇨ |
An interference pattern was made by using red light. If the red light is replaced by blue light, the fringes will becomes
Options
(a) Wider
(b) Narrower
(c) Fainter
(d) Brighter
Correct Answer:
Narrower
Explanation:
Fringe width β = λD / d
β(ʀed) / β(ʙlue) = λ(ʀed) / λ(ʙlue)
λ(ʙlue) is < λ(ʀed)
Therefore, Fringe width with blue light < β with red light.
Fringes become narrower with blue light.
Related Questions: - A particle moves in a straight line with a constant acceleration
- The distance of the closest approach of an alpha particle fired at a nucleus
- The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
- Which of the following is true for number of spectral lines in going from Lyman series
- In the diffraction pattern of a single slit
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves in a straight line with a constant acceleration
- The distance of the closest approach of an alpha particle fired at a nucleus
- The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
- Which of the following is true for number of spectral lines in going from Lyman series
- In the diffraction pattern of a single slit
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply