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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a parallel plate capacitor with plate area A and charge Q, the force on one plate
- An explosion breaks a rock into three parts in a horizontal plane
- A planar coil having 12 turns carries 15 A current. The coil is oriented with respect
- A man of 50 kg mass is standing in a gravity free space at a height
- A liquid boils when its vapour pressure equals
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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