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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
- A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground
- The work done in which of the following processes is zero?
- A wheel has moment of inertia 5 x 10⁻³ kgm² and is making 20 revolutions per sec
- The energy of the em waves is of the order of 15 keV. To which part of the spectrum
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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