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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If t₁ ̷ ₂ is the half-life of a substance, then t₃ ̷ ₄ is the time in which
- A radioactive substance contains 10000 nuclei and its halflife period is 20 days
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- After 300 days, the activity of a radioactive sample is 5000 dps
- The dimensional formula of Plancks’s constant and angular momentum are
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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