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In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
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