The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field

The Mean Free Path Of Electrons In A Metal Is Physics Question

The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m

Options

(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷

Correct Answer:

5 x 10⁷

Explanation:

E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹

Related Questions:

  1. When 4 A current flows for 2 min in an electroplating experiment,
  2. Two thin long conductors seprated by a distance d carry currents
  3. With the decrease of current in the primary coil from 2 amperes to zero value
  4. If |A x B|= √3 A.B , then the value of |A + B| is
  5. Length of second pendulum is

Topics: Electrostatics (146)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*