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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - The time period of bar magnet is doubled when magnetic field is reduced
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of bar magnet is doubled when magnetic field is reduced
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- Calculate the focal length of a reading glass of a person, if the distance
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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