⇦ | ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - When 4 A current flows for 2 min in an electroplating experiment,
- Two thin long conductors seprated by a distance d carry currents
- With the decrease of current in the primary coil from 2 amperes to zero value
- If |A x B|= √3 A.B , then the value of |A + B| is
- Length of second pendulum is
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When 4 A current flows for 2 min in an electroplating experiment,
- Two thin long conductors seprated by a distance d carry currents
- With the decrease of current in the primary coil from 2 amperes to zero value
- If |A x B|= √3 A.B , then the value of |A + B| is
- Length of second pendulum is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply