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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - Bragg’s law for X-rays is
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- For a wave propagating in a medium, identify the property that is independent
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- The process of adding impurities to the pure semiconductor is called
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bragg’s law for X-rays is
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- For a wave propagating in a medium, identify the property that is independent
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- The process of adding impurities to the pure semiconductor is called
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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