⇦ | ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - Water rises to a height h in capillary tube. If the length of capillary tube above
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- Minimum and maximum values of Poisson’s ratio for a metal lies between
- Fusion reaction takes place at high temperature because
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Water rises to a height h in capillary tube. If the length of capillary tube above
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- Minimum and maximum values of Poisson’s ratio for a metal lies between
- Fusion reaction takes place at high temperature because
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply