| ⇦ |
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - The interferance pattern is obtained with two coherent light sources of intensity
- In Young’s double silt experiment, 12 fringes are observed to be formed
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A transverse wave is represented by y = a sin (?t – kx)
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The interferance pattern is obtained with two coherent light sources of intensity
- In Young’s double silt experiment, 12 fringes are observed to be formed
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- A transverse wave is represented by y = a sin (?t – kx)
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply