| ⇦ |
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The potential difference applied to an X-ray tube is 5 kV and the current through it
- In the experiment for determination of velocity of sound in air,
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The potential difference applied to an X-ray tube is 5 kV and the current through it
- In the experiment for determination of velocity of sound in air,
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply