| ⇦ |
| ⇨ |
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
Options
(a) 4 L
(b) 2 L
(c) L/2
(d) L/4
Correct Answer:
L/2
Explanation:
At resonance ω = 1 / √(LC)
Since ω is constant,
Therefore, LC = L’C’ = L’ × 2C
⇒ L’ = L / 2
Related Questions: - A particle with total energy E is moving in a potential energy region U(x)
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- Ohm’s law is not applicable except to
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The heat dissipated in a resistance can be obtained by measuring of resistance,
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle with total energy E is moving in a potential energy region U(x)
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- Ohm’s law is not applicable except to
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The heat dissipated in a resistance can be obtained by measuring of resistance,
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply