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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- The wavelength of Kα line in copper is 1.5Å. The ionisation energy of K electron in copper is
- A beam of light of wavelength 600 nm from a distant source falls
- Which of the following is an example of ideal black body?
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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