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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
Related Questions: - The transverse nature of electromagnetic waves is proved by which of the following?
- 300j work is done in sliding a 2kg block up an inclined plane of height 10m
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The transverse nature of electromagnetic waves is proved by which of the following?
- 300j work is done in sliding a 2kg block up an inclined plane of height 10m
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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