| ⇦ |
| ⇨ |
If a charge in current of 0.01 A in one coil produces a change in magnetic flux of 1.2 x 10⁻² Wb in the outer coil, then the mutual inductance of the coils in henry is
Options
(a) 0
(b) 1.2
(c) 3
(d) 1.5
Correct Answer:
1.2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A conducting sphere of radius R is given a charge Q. The electric potential
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- For a given velocity, a projectile has the same range R for two angles of projection.
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A conducting sphere of radius R is given a charge Q. The electric potential
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- For a given velocity, a projectile has the same range R for two angles of projection.
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Magenetic flux=LXdI/dt
flux=2 x 10^(-2)
current flown in 1 sec is 0.001 amppere
ie,dI/dt = 0.01A
=>2 x 10^(-2) = L x 0.001
=>L = 2 x 10^(-2)/0.001
=>L = 2H