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₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes
Options
(a) ₉₂U²³⁴
(b) ₉₀Th²³⁴
(c) ₉₂U²³⁵
(d) ₉₃Np²³⁷
Correct Answer:
₉₀Th²³⁴
Explanation:
Emission of alpha particle, decreases the mass number by 4 and charge number by 2.
.·. Decrease in mass number = 238 – 4 = 234
Decrease in charge number = 92 – 2 = 90 ₉₀Th²³⁴ is emitted.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- Maximum range for a projectile motion is given as R. The maximum height will be
- An alternating emf given by equation e=300 sin[(100 π)t] V
- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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