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λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One mole of an ideal gas at an initial temperature of T K, does 6R joule of work
- What is the amount of energy released by deuterium and tritium fusion?
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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