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Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
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Question Type: Memory
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three identical spherical shells, each of mass m and radius r are placed
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- 40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant
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- The electric field at a distance 3R / 2 from the centre of a charged conducting
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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