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Which one of the following liquid pairs will exhibit a positive deviation from Raoult’s law
Options
(a) n-hexane and n-heptane
(b) Ethanol and chloroform
(c) Phenol and aniline
(d) Chloroform and acetone
Correct Answer:
Ethanol and chloroform
Explanation:
Since attractive forces between ethanol and chloroform will be weaker as compared to ethanol-ethanol and chloroform-chloroform, hence the tendency to escape is more and vapour pressure of solution is higher than the pure components resulting in positive deviation from Raoult’s law.
Related Questions: - 2.5 Litre of 1 M NaOH solution mixed with another 3 litre of 0.5 M NaOH solution.
- The amount of energy,which is released due to the addition of extra electron
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Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 2.5 Litre of 1 M NaOH solution mixed with another 3 litre of 0.5 M NaOH solution.
- The amount of energy,which is released due to the addition of extra electron
- The amphoteric oxide is
- The lusture of a metal is due to
- Which of the following is not the product of dehydration of
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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