| ⇦ | 
| ⇨ |
Which one of the following is present as an active ingredient in bleaching powder for bleaching action
Options
(a) CaOCl₂
(b) Ca(OCl)₂
(c) CaO₂Cl
(d) CaCl₂
Correct Answer:
Ca(OCl)₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In H₂O₂ molecules, the angle between two O-H planes is
- Boron is unable to form BF₆³⁻ because of
- Grignard reagent is prepared by the reaction between
- Chemical bond implies
- Thomas slag is
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In H₂O₂ molecules, the angle between two O-H planes is
- Boron is unable to form BF₆³⁻ because of
- Grignard reagent is prepared by the reaction between
- Chemical bond implies
- Thomas slag is
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply