⇦ | ⇨ |
Which of the following oxidation states are the most characteristic for lead and tin respectiviely?
Options
(a) 2,4
(b) 4,4
(c) 2,2
(d) 4,2
Correct Answer:
2,4
Explanation:
When ns² electrons of outermost shell do not participate in bonding then these ns² electrons are called inert pair and the effect is called inert pair effect.Due to this inert pair effect Ge,Sn and Pb of group IV have a tendency to form both +4 and + 2 ions, Now the inert pair effect increases down the group, hence the stability of M²⁺ ions increases and M⁴⁺ ions decreases down the group. For this reason, Pb²⁺ is more stable than Pb⁴⁺ and Sn⁴⁺ is more stable than Sn²⁺.
Related Questions: - What products are formed when the following compound is treated with Br₂
- Heat of formation of H₂O(g) at 25⁰C is -243 kJ,ΔE for the reaction
- Which combination is best explained by the coordinate covalent bond?
- Dalton predicted
- The element that does not show catenation among the following p-block elements is
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What products are formed when the following compound is treated with Br₂
- Heat of formation of H₂O(g) at 25⁰C is -243 kJ,ΔE for the reaction
- Which combination is best explained by the coordinate covalent bond?
- Dalton predicted
- The element that does not show catenation among the following p-block elements is
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply