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Which of the following is a representation of Gay-Lussac’s law
Options
(a) P₁V₁ = P₂V₂
(b) P₁T₁ = P₂T₂
(c) V₁T₂ = V₂T₁
(d) P₁T₂ = P₂T₁
Correct Answer:
P₁T₂ = P₂T₁
Explanation:
Gay-Lussac’s law: At constant volume, the pressure of the given mass of the gas is directly proportional to its absolute temperature.
P₁ / T₂ = P₂ / T₁(at constant volume)
⇒ P₁T₂ = P₂T₁.
Related Questions: - Schiff’s reagent is
- ‘The addition of unsymmetrical reagents to unsymmetrical alkenes occurs in such
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
- If pH of A,B,C and D are 9.5, 2.5,3.5 and 5.5 respectively, then strongest acid is
- Which would exhibit ionisation isomerism
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Schiff’s reagent is
- ‘The addition of unsymmetrical reagents to unsymmetrical alkenes occurs in such
- The IUPAC name of (CH₃)₂CH – CH₂ – CH₂Br is
- If pH of A,B,C and D are 9.5, 2.5,3.5 and 5.5 respectively, then strongest acid is
- Which would exhibit ionisation isomerism
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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