| ⇦ | 
| ⇨ |
Which of the following is a representation of Gay-Lussac’s law
Options
(a) P₁V₁ = P₂V₂
(b) P₁T₁ = P₂T₂
(c) V₁T₂ = V₂T₁
(d) P₁T₂ = P₂T₁
Correct Answer:
P₁T₂ = P₂T₁
Explanation:
Gay-Lussac’s law: At constant volume, the pressure of the given mass of the gas is directly proportional to its absolute temperature.
P₁ / T₂ = P₂ / T₁(at constant volume)
⇒ P₁T₂ = P₂T₁.
Related Questions:
- The total number of electrons present in all the p-orbitals of bromine is
- The maximum number of molecules is present in
- The basic character of the transition metal monoxides follows the order.
- Which of the following pairs of transition metal ions are the stronger oxidisi
- Which of the following acids exhibits optical activity
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply