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When two identical capacitors are in series, they have 3 μF capacitance and when in parallel 12 μF. What is the capacitance of each?
Options
(a) 6 μF
(b) 3 μF
(c) 12 μF
(d) 9 μF
Correct Answer:
6 μF
Explanation:
Let C = each capacitance
In parallel, (C + C) = 12 ⇒ 2C = 12
⇒ C = 6 μF
Related Questions: - Application of a forward bias to a P-N junction
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Application of a forward bias to a P-N junction
- In a P-N junction
- For principal quantum number n=3, the possible values of orbital quantum number
- Which of the following pairs of quantities does not have same dimensional
- A ball moving with velocity 2 m/s collides head on with another stationary ball
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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