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When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of pyridine the product obtained is
Options
(a) CH₃CH₂Cl + HCl
(b) CH₃CH₂Cl + H₂O + SO₂
(c) CH₃CH₂Cl + Cl₂ + SO₂
(d) C₂H₅Cl + HCl + SO₂
Correct Answer:
C₂H₅Cl + HCl + SO₂
Explanation:
C₂H₅OH + SOCl₂ → C₂H₅Cl + HCl + SO₂.
Related Questions: - Natural polymer amongst the following is
- In the case of auto catalysis
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- The ratio of the difference in energy between first and second Bohr orbit
- The amount of zinc required to produce 224mL of H₂ at STP on treatment with dilute H₂SO₄
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Natural polymer amongst the following is
- In the case of auto catalysis
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- The ratio of the difference in energy between first and second Bohr orbit
- The amount of zinc required to produce 224mL of H₂ at STP on treatment with dilute H₂SO₄
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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