| ⇦ | 
| ⇨ |
When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of pyridine the product obtained is
Options
(a) CH₃CH₂Cl + HCl
(b) CH₃CH₂Cl + H₂O + SO₂
(c) CH₃CH₂Cl + Cl₂ + SO₂
(d) C₂H₅Cl + HCl + SO₂
Correct Answer:
C₂H₅Cl + HCl + SO₂
Explanation:
C₂H₅OH + SOCl₂ → C₂H₅Cl + HCl + SO₂.
Related Questions: - A sample of chloroform before being used as an anaesthetic agent is tested by
- Which of the following compounds is the strongest base
- The bad smelling substance, formed by the action of alcoholic caustic potash
- Which responds to +ve iodoform test
- Cosin used to detect end point of precipitation titration by absorption is called
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sample of chloroform before being used as an anaesthetic agent is tested by
- Which of the following compounds is the strongest base
- The bad smelling substance, formed by the action of alcoholic caustic potash
- Which responds to +ve iodoform test
- Cosin used to detect end point of precipitation titration by absorption is called
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply