| ⇦ | 
| ⇨ |
When Cl₂ gas reacts with hot and concentration sodium hydroxide solution,the oxidation number of chlorine changes from
Options
(a) zero to +1 and zero to -5
(b) zero to -1 and zero to +5
(c) zero to -1 and zero to +3
(d) zero to +1 and zero to -3
Correct Answer:
zero to -1 and zero to +5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The van’t Hoff factor for a solute that associates in solution is
- Para and ortho-hydrogen differ in
- The anion, (Si₆O₁₈)¹²⁻ is present in
- In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- Ostwald’s dilution law is applicable to only
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The van’t Hoff factor for a solute that associates in solution is
- Para and ortho-hydrogen differ in
- The anion, (Si₆O₁₈)¹²⁻ is present in
- In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- Ostwald’s dilution law is applicable to only
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply