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When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - This radical can be identified by Borax bead test is
- Benzaldehyde is different from aliphatic aldehydes in its reaction towards
- The charge on the central metal ion in the complex[Ni(CO)₄] is
- Which one of the following has an aromatic character
- Four diatomic species are listed below. Identilfy the correct order in which
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- This radical can be identified by Borax bead test is
- Benzaldehyde is different from aliphatic aldehydes in its reaction towards
- The charge on the central metal ion in the complex[Ni(CO)₄] is
- Which one of the following has an aromatic character
- Four diatomic species are listed below. Identilfy the correct order in which
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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